What is the general solution for 5(sin(θ)+1)=5 ?

The general solution for 5(sin(θ)+1)=5 is θ=2pin,θ=pi+2pin

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5(sin(θ)+1)=5

5 (sin (θ) + 1) = 5

θ = 2 πn, θ = π + 2 πn

Solution steps

5 (sin (θ) + 1) = 5

Divide both sides by

5

sin (θ) + 1 = 1

Move

1

to the right side

sin (θ) = 0

General solutions for

sin (θ) = 0

θ = 0 + 2 πn, θ = π + 2 πn

Solve

θ = 0 + 2 πn : θ = 2 πn

θ = 2 πn, θ = π + 2 πn

cos (\frac{x}{2}) = \frac{3}{2}

2 sin^{2} (θ) - 3 cos (θ) = 0

\frac{1}{2} = sin (2 x)

sin (θ) = 0.4

cos (x) = 3 sin (x)

What is the general solution for 5(sin(θ)+1)=5 ?
The general solution for 5(sin(θ)+1)=5 is θ=2pin,θ=pi+2pin