What is the general solution for 7sec(θ)+9=-5 ?

The general solution for 7sec(θ)+9=-5 is θ=(2pi)/3+2pin,θ=(4pi)/3+2pin

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7sec(θ)+9=-5

7 sec (θ) + 9 = - 5

θ = \frac{2 π}{3} + 2 πn, θ = \frac{4 π}{3} + 2 πn

Solution steps

7 sec (θ) + 9 = - 5

Move

9

to the right side

7 sec (θ) = - 14

Divide both sides by

7

sec (θ) = - 2

General solutions for

sec (θ) = - 2

θ = \frac{2 π}{3} + 2 πn, θ = \frac{4 π}{3} + 2 πn

1 - 3 cos (x) = sin^{2} (x)

15 sec^{2} (x) - 20 = 0

1 - 2 tan^{2} (x) = - tan^{2} (x)

sin (x) = - \frac{1}{2}, 0 \leq x \leq 2 π

sin^{2} (x) + 2 - cos^{2} (x) = 3 sin (x)

What is the general solution for 7sec(θ)+9=-5 ?
The general solution for 7sec(θ)+9=-5 is θ=(2pi)/3+2pin,θ=(4pi)/3+2pin