What is the general solution for 2cos^2(x)+1=0 ?

The general solution for 2cos^2(x)+1=0 is No Solution for x\in\mathbb{R}

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2cos^2(x)+1=0

2 cos^{2} (x) + 1 = 0

No Solution for x \in R

Solution steps

2 cos^{2} (x) + 1 = 0

Solve by substitution

cos (x) = i \frac{1}{2}, cos (x) = - i \frac{1}{2}

cos (x) = i \frac{1}{2} :

No Solution

cos (x) = - i \frac{1}{2} :

No Solution

Combine all the solutions

No Solution for x \in R

tan (θ) = \frac{8}{15}

tan (x) = - 6

sin (7 x) + sin (x) = 0

- sin^{2} (θ) + cos^{2} (θ) = sin (θ) + 1

1 - sin (θ) = \frac{1}{2}

What is the general solution for 2cos^2(x)+1=0 ?
The general solution for 2cos^2(x)+1=0 is No Solution for x\in\mathbb{R}