What is the general solution for sin(2x-pi/3)= 1/2 ?

The general solution for sin(2x-pi/3)= 1/2 is x=pin+pi/4 ,x=pin+(7pi)/(12)

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sin(2x-pi/3)= 1/2

sin (2 x - \frac{π}{3}) = \frac{1}{2}

x = πn + \frac{π}{4}, x = πn + \frac{7 π}{12}

Solution steps

sin (2 x - \frac{π}{3}) = \frac{1}{2}

General solutions for

sin (2 x - \frac{π}{3}) = \frac{1}{2}

2 x - \frac{π}{3} = \frac{π}{6} + 2 πn, 2 x - \frac{π}{3} = \frac{5 π}{6} + 2 πn

Solve

2 x - \frac{π}{3} = \frac{π}{6} + 2 πn : x = πn + \frac{π}{4}

Solve

2 x - \frac{π}{3} = \frac{5 π}{6} + 2 πn : x = πn + \frac{7 π}{12}

x = πn + \frac{π}{4}, x = πn + \frac{7 π}{12}

23 sin (2Θ) = 3, 0 \leq Θ \leq 2 π

4 cos^{2} (x) = 5 + 4 sin (x)

2 sin^{2} (x) + 3 sin (x) = 0

cos^{2} (x) - sin (x) = 1

sec^{2} (x) - 5 tan (x) = - 3

What is the general solution for sin(2x-pi/3)= 1/2 ?
The general solution for sin(2x-pi/3)= 1/2 is x=pin+pi/4 ,x=pin+(7pi)/(12)