What is the general solution for sin(x+pi/4)=(sqrt(3))/2 ?

The general solution for sin(x+pi/4)=(sqrt(3))/2 is x=2pin+pi/(12),x=2pin+(5pi)/(12)

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sin(x+pi/4)=(sqrt(3))/2

Solution

sin (x + \frac{π}{4}) = \frac{3}{2}

Solution

x = 2 πn + \frac{π}{12}, x = 2 πn + \frac{5 π}{12}

Degrees

x = 1 5^{\circ} + 36 0^{\circ} n, x = 7 5^{\circ} + 36 0^{\circ} n

Solution steps

sin (x + \frac{π}{4}) = \frac{3}{2}

General solutions for

sin (x + \frac{π}{4}) = \frac{3}{2}

sin (x)

periodicity table with

2 πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} sin (x) 0 \frac{1}{2} \frac{2}{2} \frac{3}{2} 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} sin (x) 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2}

x + \frac{π}{4} = \frac{π}{3} + 2 πn, x + \frac{π}{4} = \frac{2 π}{3} + 2 πn

x + \frac{π}{4} = \frac{π}{3} + 2 πn, x + \frac{π}{4} = \frac{2 π}{3} + 2 πn

Solve

x + \frac{π}{4} = \frac{π}{3} + 2 πn : x = 2 πn + \frac{π}{12}

x + \frac{π}{4} = \frac{π}{3} + 2 πn

Move

\frac{π}{4}

to the right side

x + \frac{π}{4} = \frac{π}{3} + 2 πn

Subtract

\frac{π}{4}

from both sides

x + \frac{π}{4} - \frac{π}{4} = \frac{π}{3} + 2 πn - \frac{π}{4}

Simplify

x + \frac{π}{4} - \frac{π}{4} = \frac{π}{3} + 2 πn - \frac{π}{4}

Simplify

x + \frac{π}{4} - \frac{π}{4} : x

x + \frac{π}{4} - \frac{π}{4}

Add similar elements:

\frac{π}{4} - \frac{π}{4} = 0

= x

Simplify

\frac{π}{3} + 2 πn - \frac{π}{4} : 2 πn + \frac{π}{12}

\frac{π}{3} + 2 πn - \frac{π}{4}

Group like terms

= 2 πn + \frac{π}{3} - \frac{π}{4}

Least Common Multiplier of

3, 4 : 12

3, 4

Least Common Multiplier (LCM)

Prime factorization of

3 : 3

3

3

is a prime number, therefore no factorization is possible

= 3

Prime factorization of

4 : 2 \cdot 2

4

4

divides by

24 = 2 \cdot 2

= 2 \cdot 2

Multiply each factor the greatest number of times it occurs in either

3

4

= 3 \cdot 2 \cdot 2

Multiply the numbers:

3 \cdot 2 \cdot 2 = 12

= 12

Adjust Fractions based on the LCM

Multiply each numerator by the same amount needed to multiply its

corresponding denominator to turn it into the LCM

12

For

\frac{π}{3} :

multiply the denominator and numerator by

4

\frac{π}{3} = \frac{π 4}{3 \cdot 4} = \frac{π 4}{12}

For

\frac{π}{4} :

multiply the denominator and numerator by

3

\frac{π}{4} = \frac{π 3}{4 \cdot 3} = \frac{π 3}{12}

= \frac{π 4}{12} - \frac{π 3}{12}

Since the denominators are equal, combine the fractions:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{π 4 - π 3}{12}

Add similar elements:

4 π - 3 π = π

= 2 πn + \frac{π}{12}

x = 2 πn + \frac{π}{12}

x = 2 πn + \frac{π}{12}

x = 2 πn + \frac{π}{12}

Solve

x + \frac{π}{4} = \frac{2 π}{3} + 2 πn : x = 2 πn + \frac{5 π}{12}

x + \frac{π}{4} = \frac{2 π}{3} + 2 πn

Move

\frac{π}{4}

to the right side

x + \frac{π}{4} = \frac{2 π}{3} + 2 πn

Subtract

\frac{π}{4}

from both sides

x + \frac{π}{4} - \frac{π}{4} = \frac{2 π}{3} + 2 πn - \frac{π}{4}

Simplify

x + \frac{π}{4} - \frac{π}{4} = \frac{2 π}{3} + 2 πn - \frac{π}{4}

Simplify

x + \frac{π}{4} - \frac{π}{4} : x

x + \frac{π}{4} - \frac{π}{4}

Add similar elements:

\frac{π}{4} - \frac{π}{4} = 0

= x

Simplify

\frac{2 π}{3} + 2 πn - \frac{π}{4} : 2 πn + \frac{5 π}{12}

\frac{2 π}{3} + 2 πn - \frac{π}{4}

Group like terms

= 2 πn - \frac{π}{4} + \frac{2 π}{3}

Least Common Multiplier of

4, 3 : 12

4, 3

Least Common Multiplier (LCM)

Prime factorization of

4 : 2 \cdot 2

4

4

divides by

24 = 2 \cdot 2

= 2 \cdot 2

Prime factorization of

3 : 3

3

3

is a prime number, therefore no factorization is possible

= 3

Multiply each factor the greatest number of times it occurs in either

4

3

= 2 \cdot 2 \cdot 3

Multiply the numbers:

2 \cdot 2 \cdot 3 = 12

= 12

Adjust Fractions based on the LCM

Multiply each numerator by the same amount needed to multiply its

corresponding denominator to turn it into the LCM

12

For

\frac{π}{4} :

multiply the denominator and numerator by

3

\frac{π}{4} = \frac{π 3}{4 \cdot 3} = \frac{π 3}{12}

For

\frac{2 π}{3} :

multiply the denominator and numerator by

4

\frac{2 π}{3} = \frac{2 π 4}{3 \cdot 4} = \frac{8 π}{12}

= - \frac{π 3}{12} + \frac{8 π}{12}

Since the denominators are equal, combine the fractions:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{- π 3 + 8 π}{12}

Add similar elements:

- 3 π + 8 π = 5 π

= 2 πn + \frac{5 π}{12}

x = 2 πn + \frac{5 π}{12}

x = 2 πn + \frac{5 π}{12}

x = 2 πn + \frac{5 π}{12}

x = 2 πn + \frac{π}{12}, x = 2 πn + \frac{5 π}{12}

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Frequently Asked Questions (FAQ)

What is the general solution for sin(x+pi/4)=(sqrt(3))/2 ?
The general solution for sin(x+pi/4)=(sqrt(3))/2 is x=2pin+pi/(12),x=2pin+(5pi)/(12)