What is the general solution for 9tan(θ)+13=2tan(θ)+6 ?

The general solution for 9tan(θ)+13=2tan(θ)+6 is θ=(3pi)/4+pin

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9tan(θ)+13=2tan(θ)+6

9 tan (θ) + 13 = 2 tan (θ) + 6

θ = \frac{3 π}{4} + πn

Solution steps

9 tan (θ) + 13 = 2 tan (θ) + 6

Solve by substitution

tan (θ) = - 1

tan (θ) = - 1 : θ = \frac{3 π}{4} + πn

Combine all the solutions

θ = \frac{3 π}{4} + πn

2 = 3 sin (∣ 5 x ∣) + 1

sin (θ) = - \frac{1}{3}

sin (θ) = - \frac{1}{4}

sin (θ) cos (θ) = \frac{1}{2}

cos (θ) = \frac{- 3}{2}

What is the general solution for 9tan(θ)+13=2tan(θ)+6 ?
The general solution for 9tan(θ)+13=2tan(θ)+6 is θ=(3pi)/4+pin