What is the general solution for tan(θ)+1/(sqrt(3))=0 ?

The general solution for tan(θ)+1/(sqrt(3))=0 is θ=(5pi)/6+pin

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tan(θ)+1/(sqrt(3))=0

tan (θ) + \frac{1}{3} = 0

θ = \frac{5 π}{6} + πn

Solution steps

tan (θ) + \frac{1}{3} = 0

Move

\frac{1}{3}

to the right side

tan (θ) = - \frac{3}{3}

General solutions for

tan (θ) = - \frac{3}{3}

θ = \frac{5 π}{6} + πn

12 cos^{2} (x) - 3 = 0

csc^{2} (θ) + 4 csc (θ) - 5 = 0

cos^{2} (x) - cos (x) = 0, 0 \leq x \leq 2 π

\frac{sin ( 2 x )}{cos ( x )} = 2, 0 \leq x \leq π

sec (θ) = - 4

What is the general solution for tan(θ)+1/(sqrt(3))=0 ?
The general solution for tan(θ)+1/(sqrt(3))=0 is θ=(5pi)/6+pin