What is the general solution for cos(2x)+sin^2(x)=0 ?

The general solution for cos(2x)+sin^2(x)=0 is x= pi/2+2pin,x=(3pi)/2+2pin

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cos(2x)+sin^2(x)=0

cos (2 x) + sin^{2} (x) = 0

x = \frac{π}{2} + 2 πn, x = \frac{3 π}{2} + 2 πn

Solution steps

cos (2 x) + sin^{2} (x) = 0

Rewrite using trig identities

cos^{2} (x) = 0

Apply rule

x^{n} = 0 \Rightarrow x = 0

cos (x) = 0

General solutions for

cos (x) = 0

x = \frac{π}{2} + 2 πn, x = \frac{3 π}{2} + 2 πn

1 + cos (x) = 3 sin (x)

3 sin (x) = 0

1 + sin (x) = cos (x)

sin (x + \frac{π}{2}) - cos^{2} (x) = 0

9 tan^{2} (θ) - 4 = 0

What is the general solution for cos(2x)+sin^2(x)=0 ?
The general solution for cos(2x)+sin^2(x)=0 is x= pi/2+2pin,x=(3pi)/2+2pin