What is the general solution for 3cos(θ)+1=1 ?

The general solution for 3cos(θ)+1=1 is θ= pi/2+2pin,θ=(3pi)/2+2pin

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3cos(θ)+1=1

3 cos (θ) + 1 = 1

θ = \frac{π}{2} + 2 πn, θ = \frac{3 π}{2} + 2 πn

Solution steps

3 cos (θ) + 1 = 1

Subtract

1

from both sides

3 cos (θ) + 1 - 1 = 1 - 1

Simplify

3 cos (θ) = 0

Divide both sides by

3

cos (θ) = 0

General solutions for

cos (θ) = 0

θ = \frac{π}{2} + 2 πn, θ = \frac{3 π}{2} + 2 πn

sin (θ) = 3

2 cos (x) csc (x) = 2 cos (x)

- 2 cos^{2} (x) = 3 cos (x) + 1

1 + sec (x) = 3

tan (\frac{θ}{2} + \frac{π}{4}) = 1

What is the general solution for 3cos(θ)+1=1 ?
The general solution for 3cos(θ)+1=1 is θ= pi/2+2pin,θ=(3pi)/2+2pin