What is the general solution for sin^2(θ)=1 ?

The general solution for sin^2(θ)=1 is θ= pi/2+2pin,θ=(3pi)/2+2pin

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sin^2(θ)=1

sin^{2} (θ) = 1

θ = \frac{π}{2} + 2 πn, θ = \frac{3 π}{2} + 2 πn

Solution steps

sin^{2} (θ) = 1

Solve by substitution

sin (θ) = 1, sin (θ) = - 1

sin (θ) = 1 : θ = \frac{π}{2} + 2 πn

sin (θ) = - 1 : θ = \frac{3 π}{2} + 2 πn

Combine all the solutions

θ = \frac{π}{2} + 2 πn, θ = \frac{3 π}{2} + 2 πn

sin^{2} (x) - 5 cos (x) + 5 = 0

4 sin (x) cos (x) + cos (x) = 0

sin (2 x) = \frac{1}{2}

- 2 sin^{2} (x) = 3 sin (x) + 1

cos (x) cos (2 x) + sin (x) sin (2 x) = \frac{1}{2}

What is the general solution for sin^2(θ)=1 ?
The general solution for sin^2(θ)=1 is θ= pi/2+2pin,θ=(3pi)/2+2pin