What is the general solution for 1-sin^2(x)=0 ?

The general solution for 1-sin^2(x)=0 is x= pi/2+2pin,x=(3pi)/2+2pin

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1-sin^2(x)=0

1 - sin^{2} (x) = 0

x = \frac{π}{2} + 2 πn, x = \frac{3 π}{2} + 2 πn

Solution steps

1 - sin^{2} (x) = 0

Solve by substitution

sin (x) = 1, sin (x) = - 1

sin (x) = 1 : x = \frac{π}{2} + 2 πn

sin (x) = - 1 : x = \frac{3 π}{2} + 2 πn

Combine all the solutions

x = \frac{π}{2} + 2 πn, x = \frac{3 π}{2} + 2 πn

sin (\frac{x}{2}) = - \frac{1}{2}

cot (x) + 1 = csc (x)

2 cos^{2} (x) + 4 sin^{2} (x) = 3

x, sin (x) = 1

4 sec (θ) + 5 = 0

What is the general solution for 1-sin^2(x)=0 ?
The general solution for 1-sin^2(x)=0 is x= pi/2+2pin,x=(3pi)/2+2pin