What is the general solution for 8cos(12x)+4=-4 ?

The general solution for 8cos(12x)+4=-4 is x= pi/(12)+(pin)/6

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8cos(12x)+4=-4

8 cos (12 x) + 4 = - 4

x = \frac{π}{12} + \frac{πn}{6}

Solution steps

8 cos (12 x) + 4 = - 4

Move

4

to the right side

8 cos (12 x) = - 8

Divide both sides by

8

cos (12 x) = - 1

General solutions for

cos (12 x) = - 1

12 x = π + 2 πn

Solve

12 x = π + 2 πn : x = \frac{π}{12} + \frac{πn}{6}

x = \frac{π}{12} + \frac{πn}{6}

12 tan^{3} (x) = 4 tan (x)

cos (2 θ) = 3 sin (θ) - 1

sin (4 x) = - 1

cos (2 x) = sin (2 x)

cos (2 x) = \frac{1}{2}, 0 \leq x \leq 2 π

What is the general solution for 8cos(12x)+4=-4 ?
The general solution for 8cos(12x)+4=-4 is x= pi/(12)+(pin)/6