What is the general solution for cos(θ)= 8/17 ,270<θ<360 ?

The general solution for cos(θ)= 8/17 ,270<θ<360 is θ=360-1.08083…

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cos(θ)= 8/17 ,270<θ<360

cos (θ) = \frac{8}{17}, 27 0^{\circ} < θ < 36 0^{\circ}

θ = 36 0^{\circ} - 1.08083 \dots

Solution steps

cos (θ) = \frac{8}{17}, 27 0^{\circ} < θ < 36 0^{\circ}

Apply trig inverse properties

θ = arccos (\frac{8}{17}) + 36 0^{\circ} n, θ = 36 0^{\circ} - arccos (\frac{8}{17}) + 36 0^{\circ} n

Solutions for the range

27 0^{\circ} < θ < 36 0^{\circ}

θ = 36 0^{\circ} - arccos (\frac{8}{17})

Show solutions in decimal form

θ = 36 0^{\circ} - 1.08083 \dots

2 csc (θ) - 3 = 0

cos (x - \frac{π}{7}) = \frac{- 2}{2}, 0 \leq x \leq 2 π

sin (2 θ) = sin (θ)

25 cos^{2} (θ) - 1 = 0

cos (θ) = \frac{4}{7}

What is the general solution for cos(θ)= 8/17 ,270<θ<360 ?
The general solution for cos(θ)= 8/17 ,270<θ<360 is θ=360-1.08083…