What is the general solution for cos(x+1)=0 ?

The general solution for cos(x+1)=0 is x= pi/2+2pin-1,x=(3pi)/2+2pin-1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

cos(x+1)=0

cos (x + 1) = 0

x = \frac{π}{2} + 2 πn - 1, x = \frac{3 π}{2} + 2 πn - 1

Degrees

x = 32.70422 \dots^{\circ} + 36 0^{\circ} n, x = 212.70422 \dots^{\circ} + 36 0^{\circ} n

Solution steps

cos (x + 1) = 0

General solutions for

cos (x + 1) = 0

cos (x)

periodicity table with

2 πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} cos (x) 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} cos (x) - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2} 0 \frac{1}{2} \frac{2}{2} \frac{3}{2}

x + 1 = \frac{π}{2} + 2 πn, x + 1 = \frac{3 π}{2} + 2 πn

x + 1 = \frac{π}{2} + 2 πn, x + 1 = \frac{3 π}{2} + 2 πn

Solve

x + 1 = \frac{π}{2} + 2 πn : x = \frac{π}{2} + 2 πn - 1

x + 1 = \frac{π}{2} + 2 πn

Move

1

to the right side

x + 1 = \frac{π}{2} + 2 πn

Subtract

1

from both sides

x + 1 - 1 = \frac{π}{2} + 2 πn - 1

Simplify

x = \frac{π}{2} + 2 πn - 1

x = \frac{π}{2} + 2 πn - 1