What is the general solution for sin(θ)-1=-1 ?

The general solution for sin(θ)-1=-1 is θ=2pin,θ=pi+2pin

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sin(θ)-1=-1

sin (θ) - 1 = - 1

θ = 2 πn, θ = π + 2 πn

Solution steps

sin (θ) - 1 = - 1

Add

1

to both sides

sin (θ) - 1 + 1 = - 1 + 1

Simplify

sin (θ) = 0

General solutions for

sin (θ) = 0

θ = 0 + 2 πn, θ = π + 2 πn

Solve

θ = 0 + 2 πn : θ = 2 πn

θ = 2 πn, θ = π + 2 πn

3 + sin (x) = 3 cos^{2} (x)

cot (θ) = 3

sin^{2} (x) + 4 sin (x) = 0

(tan (x) - 1) (sec (x) - 1) = 0

4 - 8 sin^{2} (x) = 0

What is the general solution for sin(θ)-1=-1 ?
The general solution for sin(θ)-1=-1 is θ=2pin,θ=pi+2pin