What is the value of sin^2(120)+cos^2(120) ?

The value of sin^2(120)+cos^2(120) is 1

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sin^2(120)+cos^2(120)

sin^{2} (12 0^{\circ}) + cos^{2} (12 0^{\circ})

1

Solution steps

sin^{2} (12 0^{\circ}) + cos^{2} (12 0^{\circ})

Use the following trivial identity:

sin (12 0^{\circ}) = \frac{3}{2}

Use the following trivial identity:

cos (12 0^{\circ}) = - \frac{1}{2}

= (\frac{3}{2})^{2} + (- \frac{1}{2})^{2}

Simplify

(\frac{3}{2})^{2} + (- \frac{1}{2})^{2} : 1

= 1

2 sin^{2} (x) = 1

sin (2 x) = sin (x)

cos (4 5^{\circ})

arctan (- \frac{1}{3})

cos (\frac{π}{5})

What is the value of sin^2(120)+cos^2(120) ?
The value of sin^2(120)+cos^2(120) is 1