What is the general solution for -sin(2x)*2=0 ?

The general solution for -sin(2x)*2=0 is x=pin,x= pi/2+pin

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-sin(2x)*2=0

- sin (2 x) \cdot 2 = 0

x = πn, x = \frac{π}{2} + πn

Solution steps

- sin (2 x) \cdot 2 = 0

Divide both sides by

- 2

sin (2 x) = 0

General solutions for

sin (2 x) = 0

2 x = 0 + 2 πn, 2 x = π + 2 πn

Solve

2 x = 0 + 2 πn : x = πn

Solve

2 x = π + 2 πn : x = \frac{π}{2} + πn

x = πn, x = \frac{π}{2} + πn

sin (x) = 3 cos (x)

cos (2 t) = cos (t)

cos (x) + cos (2 x) + cos (3 x) = 0

2 cot (θ) - 7 = 0

sec (x) = - \frac{2 3}{3}

What is the general solution for -sin(2x)*2=0 ?
The general solution for -sin(2x)*2=0 is x=pin,x= pi/2+pin