What is the general solution for 4cos(x+70)=3 ?

The general solution for 4cos(x+70)=3 is x=0.72273…+360n-70,x=360-0.72273…+360n-70

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4cos(x+70)=3

4 cos (x + 7 0^{\circ}) = 3

x = 0.72273 \dots + 36 0^{\circ} n - 7 0^{\circ}, x = 36 0^{\circ} - 0.72273 \dots + 36 0^{\circ} n - 7 0^{\circ}

Solution steps

4 cos (x + 7 0^{\circ}) = 3

Divide both sides by

4

cos (x + 7 0^{\circ}) = \frac{3}{4}

Apply trig inverse properties

x + 7 0^{\circ} = arccos (\frac{3}{4}) + 36 0^{\circ} n, x + 7 0^{\circ} = 36 0^{\circ} - arccos (\frac{3}{4}) + 36 0^{\circ} n

Solve

x + 7 0^{\circ} = arccos (\frac{3}{4}) + 36 0^{\circ} n : x = arccos (\frac{3}{4}) + 36 0^{\circ} n - 7 0^{\circ}

Solve

x + 7 0^{\circ} = 36 0^{\circ} - arccos (\frac{3}{4}) + 36 0^{\circ} n : x = 36 0^{\circ} - arccos (\frac{3}{4}) + 36 0^{\circ} n - 7 0^{\circ}

x = arccos (\frac{3}{4}) + 36 0^{\circ} n - 7 0^{\circ}, x = 36 0^{\circ} - arccos (\frac{3}{4}) + 36 0^{\circ} n - 7 0^{\circ}

Show solutions in decimal form

x = 0.72273 \dots + 36 0^{\circ} n - 7 0^{\circ}, x = 36 0^{\circ} - 0.72273 \dots + 36 0^{\circ} n - 7 0^{\circ}

4 cos (2 x) = 0

tan (3 x) = - \frac{3}{3}

tan^{2} (x) + 3 = 2 sec^{2} (x)

8 sin^{2} (θ) - 2 = 0

4 sin (2 x) sin (x) = 4 cos (x)

What is the general solution for 4cos(x+70)=3 ?
The general solution for 4cos(x+70)=3 is x=0.72273…+360n-70,x=360-0.72273…+360n-70