What is the general solution for 6sin^2(θ)-13sin(θ)+7=0 ?

The general solution for 6sin^2(θ)-13sin(θ)+7=0 is θ= pi/2+2pin

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6sin^2(θ)-13sin(θ)+7=0

6 sin^{2} (θ) - 13 sin (θ) + 7 = 0

θ = \frac{π}{2} + 2 πn

Solution steps

6 sin^{2} (θ) - 13 sin (θ) + 7 = 0

Solve by substitution

sin (θ) = \frac{7}{6}, sin (θ) = 1

sin (θ) = \frac{7}{6} :

No Solution

sin (θ) = 1 : θ = \frac{π}{2} + 2 πn

Combine all the solutions

θ = \frac{π}{2} + 2 πn

sin (x) = 0.1

3 sin^{2} (x) + 6 sin (x) + 3 = 0

3 sin (x) - 4 = sin (x) - 2

sin (θ) = - \frac{5}{6}

sec (θ) = 0

What is the general solution for 6sin^2(θ)-13sin(θ)+7=0 ?
The general solution for 6sin^2(θ)-13sin(θ)+7=0 is θ= pi/2+2pin