What is the general solution for -4cos(4x)=0 ?

The general solution for -4cos(4x)=0 is x= pi/8+(pin)/2 ,x=(3pi)/8+(pin)/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

-4cos(4x)=0

- 4 cos (4 x) = 0

x = \frac{π}{8} + \frac{πn}{2}, x = \frac{3 π}{8} + \frac{πn}{2}

Solution steps

- 4 cos (4 x) = 0

Divide both sides by

- 4

cos (4 x) = 0

General solutions for

cos (4 x) = 0

4 x = \frac{π}{2} + 2 πn, 4 x = \frac{3 π}{2} + 2 πn

Solve

4 x = \frac{π}{2} + 2 πn : x = \frac{π}{8} + \frac{πn}{2}

Solve

4 x = \frac{3 π}{2} + 2 πn : x = \frac{3 π}{8} + \frac{πn}{2}

x = \frac{π}{8} + \frac{πn}{2}, x = \frac{3 π}{8} + \frac{πn}{2}

4 csc^{2} (θ) - 25 = 0

tan (3 x) = 5

x, cos (x) - sin (x) = 0

tan (θ) = 2 sin (θ)

0 = - sin (x) + cos (x)

What is the general solution for -4cos(4x)=0 ?
The general solution for -4cos(4x)=0 is x= pi/8+(pin)/2 ,x=(3pi)/8+(pin)/2