What is the general solution for 2sin^2(θ)-sqrt(3)sin(θ)=0 ?

The general solution for 2sin^2(θ)-sqrt(3)sin(θ)=0 is θ= pi/3+2pin,θ=(2pi)/3+2pin,θ=2pin,θ=pi+2pin

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2sin^2(θ)-sqrt(3)sin(θ)=0

2 sin^{2} (θ) - 3 sin (θ) = 0

θ = \frac{π}{3} + 2 πn, θ = \frac{2 π}{3} + 2 πn, θ = 2 πn, θ = π + 2 πn

Solution steps

2 sin^{2} (θ) - 3 sin (θ) = 0

Solve by substitution

sin (θ) = \frac{3}{2}, sin (θ) = 0

sin (θ) = \frac{3}{2} : θ = \frac{π}{3} + 2 πn, θ = \frac{2 π}{3} + 2 πn

sin (θ) = 0 : θ = 2 πn, θ = π + 2 πn

Combine all the solutions

θ = \frac{π}{3} + 2 πn, θ = \frac{2 π}{3} + 2 πn, θ = 2 πn, θ = π + 2 πn

sec^{2} (x) + 2 tan (x) = 4

tan (\frac{x}{5}) + 3 = 0

cos (2 x) - 2 cos (x) = - 1

2 sin (x + \frac{π}{2}) + 3 tan (π - x) = 0

sin (x) = 0.27

What is the general solution for 2sin^2(θ)-sqrt(3)sin(θ)=0 ?
The general solution for 2sin^2(θ)-sqrt(3)sin(θ)=0 is θ= pi/3+2pin,θ=(2pi)/3+2pin,θ=2pin,θ=pi+2pin