What is the general solution for tan(x)sin(x)-tan(x)=0 ?

The general solution for tan(x)sin(x)-tan(x)=0 is x=pin

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

tan(x)sin(x)-tan(x)=0

tan (x) sin (x) - tan (x) = 0

x = πn

Solution steps

tan (x) sin (x) - tan (x) = 0

Factor

tan (x) sin (x) - tan (x) : tan (x) (sin (x) - 1)

tan (x) (sin (x) - 1) = 0

Solving each part separately

tan (x) = 0 or sin (x) - 1 = 0

tan (x) = 0 : x = πn

sin (x) - 1 = 0 : x = \frac{π}{2} + 2 πn

Combine all the solutions

x = πn, x = \frac{π}{2} + 2 πn

Since the equation is undefined for:

\frac{π}{2} + 2 πn

x = πn

cos^{2} (θ) - 7 cos (θ) + 12 = 0

cos^{2} (x) = cos^{2} (\frac{x}{2})

csc^{2} (θ) - csc (θ) - 20 = 0

sec^{2} (θ) + 7 sec (θ) + 6 = 0

cos (x) = \frac{3}{8}

What is the general solution for tan(x)sin(x)-tan(x)=0 ?
The general solution for tan(x)sin(x)-tan(x)=0 is x=pin