What is the general solution for tan(x)sin(x)-tan(x)=0 ?

The general solution for tan(x)sin(x)-tan(x)=0 is x=pin

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

tan(x)sin(x)-tan(x)=0

tan (x) sin (x) - tan (x) = 0

x = πn

Degrees

x = 0^{\circ} + 18 0^{\circ} n

Solution steps

tan (x) sin (x) - tan (x) = 0

Factor

tan (x) sin (x) - tan (x) : tan (x) (sin (x) - 1)

tan (x) sin (x) - tan (x)

Factor out common term

tan (x)

= tan (x) (sin (x) - 1)

tan (x) (sin (x) - 1) = 0

Solving each part separately

tan (x) = 0 or sin (x) - 1 = 0

tan (x) = 0 : x = πn

tan (x) = 0

General solutions for

tan (x) = 0

tan (x)

periodicity table with

πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} tan (x) 0 \frac{3}{3} 13 \pm \infty - 3 - 1 - \frac{3}{3}

x = 0 + πn

x = 0 + πn

Solve

x = 0 + πn : x = πn

x = 0 + πn

0 + πn = πn

x = πn

x = πn

sin (x) - 1 = 0 : x = \frac{π}{2} + 2 πn

sin (x) - 1 = 0

Move

1

to the right side

sin (x) - 1 = 0

Add

1

to both sides

sin (x) - 1 + 1 = 0 + 1

Simplify

sin (x) = 1

sin (x) = 1

General solutions for

sin (x) = 1

sin (x)

periodicity table with

2 πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} sin (x) 0 \frac{1}{2} \frac{2}{2} \frac{3}{2} 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} sin (x) 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2}

x = \frac{π}{2} + 2 πn

x = \frac{π}{2} + 2 πn

Combine all the solutions

x = πn, x = \frac{π}{2} + 2 πn

Since the equation is undefined for:

\frac{π}{2} + 2 πn

x = πn

cos^{2} (θ) - 7 cos (θ) + 12 = 0

cos^{2} (x) = cos^{2} (\frac{x}{2})

csc^{2} (θ) - csc (θ) - 20 = 0

sec^{2} (θ) + 7 sec (θ) + 6 = 0

cos (x) = \frac{3}{8}

What is the general solution for tan(x)sin(x)-tan(x)=0 ?
The general solution for tan(x)sin(x)-tan(x)=0 is x=pin