What is the general solution for -2cos(3θ)=1 ?

The general solution for -2cos(3θ)=1 is θ=(2pi)/9+(2pin)/3 ,θ=(4pi)/9+(2pin)/3

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-2cos(3θ)=1

- 2 cos (3 θ) = 1

θ = \frac{2 π}{9} + \frac{2 πn}{3}, θ = \frac{4 π}{9} + \frac{2 πn}{3}

Solution steps

- 2 cos (3 θ) = 1

Divide both sides by

- 2

cos (3 θ) = - \frac{1}{2}

General solutions for

cos (3 θ) = - \frac{1}{2}

3 θ = \frac{2 π}{3} + 2 πn, 3 θ = \frac{4 π}{3} + 2 πn

Solve

3 θ = \frac{2 π}{3} + 2 πn : θ = \frac{2 π}{9} + \frac{2 πn}{3}

Solve

3 θ = \frac{4 π}{3} + 2 πn : θ = \frac{4 π}{9} + \frac{2 πn}{3}

θ = \frac{2 π}{9} + \frac{2 πn}{3}, θ = \frac{4 π}{9} + \frac{2 πn}{3}

sec^{2} (x) + 0.5 tan (x) - 1 = 0

cos (2 x) = sin (x), 0 \leq x \leq 2 π

tan (x - \frac{π}{2}) = 1

5 cos (x) = 4 sin (x) + 4

6 sec^{2} (x) tan (x) = 8 tan (x)

What is the general solution for -2cos(3θ)=1 ?
The general solution for -2cos(3θ)=1 is θ=(2pi)/9+(2pin)/3 ,θ=(4pi)/9+(2pin)/3