What is the general solution for 3cos(x)=2sin^2(x) ?

The general solution for 3cos(x)=2sin^2(x) is x= pi/3+2pin,x=(5pi)/3+2pin

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

3cos(x)=2sin^2(x)

3 cos (x) = 2 sin^{2} (x)

x = \frac{π}{3} + 2 πn, x = \frac{5 π}{3} + 2 πn

Solution steps

3 cos (x) = 2 sin^{2} (x)

Subtract

2 sin^{2} (x)

from both sides

3 cos (x) - 2 sin^{2} (x) = 0

Rewrite using trig identities

- (1 - cos^{2} (x)) \cdot 2 + 3 cos (x) = 0

Solve by substitution

cos (x) = \frac{1}{2}, cos (x) = - 2

cos (x) = \frac{1}{2} : x = \frac{π}{3} + 2 πn, x = \frac{5 π}{3} + 2 πn

cos (x) = - 2 :

No Solution

Combine all the solutions

x = \frac{π}{3} + 2 πn, x = \frac{5 π}{3} + 2 πn

2 sec^{2} (x) - tan^{4} (x) = - 1

4 sin (θ) = 2

6 cos^{2} (x) = 3

3 sin (x) + 3 = sin (x)

4 sec^{2} (x) - 7 tan^{2} (x) = 3

What is the general solution for 3cos(x)=2sin^2(x) ?
The general solution for 3cos(x)=2sin^2(x) is x= pi/3+2pin,x=(5pi)/3+2pin