What is the general solution for cos^2(θ)-cos(θ)-2=0 ?

The general solution for cos^2(θ)-cos(θ)-2=0 is θ=pi+2pin

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cos^2(θ)-cos(θ)-2=0

cos^{2} (θ) - cos (θ) - 2 = 0

θ = π + 2 πn

Solution steps

cos^{2} (θ) - cos (θ) - 2 = 0

Solve by substitution

cos (θ) = 2, cos (θ) = - 1

cos (θ) = 2 :

No Solution

cos (θ) = - 1 : θ = π + 2 πn

Combine all the solutions

θ = π + 2 πn

2 sin (3 x) = - 1

8 sin^{2} (θ) + 2 sin (θ) - 1 = 0

tan (θ) = 6

sin (4 x) = \frac{1}{2}

cos (x) - sin (x) = 0, 0 \leq x < 2 π

What is the general solution for cos^2(θ)-cos(θ)-2=0 ?
The general solution for cos^2(θ)-cos(θ)-2=0 is θ=pi+2pin