What is the general solution for solvefor x,y=sin((pix)/2) ?

The general solution for solvefor x,y=sin((pix)/2) is x=(2arcsin(y))/pi+4n,x=2+(2arcsin(-y))/pi+4n

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solvefor x,y=sin((pix)/2)

solve for

x, y = sin (\frac{π x}{2})

x = \frac{2 arcsin ( y )}{π} + 4 n, x = 2 + \frac{2 arcsin ( - y )}{π} + 4 n

Solution steps

y = sin (\frac{π x}{2})

Switch sides

sin (\frac{π x}{2}) = y

Apply trig inverse properties

\frac{π x}{2} = arcsin (y) + 2 πn, \frac{π x}{2} = π + arcsin (- y) + 2 πn

Solve

\frac{π x}{2} = arcsin (y) + 2 πn : x = \frac{2 arcsin ( y )}{π} + 4 n

Solve

\frac{π x}{2} = π + arcsin (- y) + 2 πn : x = 2 + \frac{2 arcsin ( - y )}{π} + 4 n

x = \frac{2 arcsin ( y )}{π} + 4 n, x = 2 + \frac{2 arcsin ( - y )}{π} + 4 n

5 sin (x) - 5 cos (x) = 2

6 cos^{2} (x) - cos (x) - 2 = 0

cos (x) - sin (x) = 0, \forall 0 \leq x < 2 π

3 sec (θ) + 2 = 8

sin^{2} (x) = 0.75

What is the general solution for solvefor x,y=sin((pix)/2) ?
The general solution for solvefor x,y=sin((pix)/2) is x=(2arcsin(y))/pi+4n,x=2+(2arcsin(-y))/pi+4n