What is the general solution for 5tan(θ)-7=0 ?

The general solution for 5tan(θ)-7=0 is θ=0.95054…+pin

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

5tan(θ)-7=0

5 tan (θ) - 7 = 0

θ = 0.95054 \dots + πn

Degrees

θ = 54.46232 \dots^{\circ} + 18 0^{\circ} n

Solution steps

5 tan (θ) - 7 = 0

Move

7

to the right side

5 tan (θ) - 7 = 0

Add

7

to both sides

5 tan (θ) - 7 + 7 = 0 + 7

Simplify

5 tan (θ) = 7

5 tan (θ) = 7

Divide both sides by

5

5 tan (θ) = 7

Divide both sides by

5

\frac{5 tan ( θ )}{5} = \frac{7}{5}

Simplify

tan (θ) = \frac{7}{5}

tan (θ) = \frac{7}{5}

Apply trig inverse properties

tan (θ) = \frac{7}{5}

General solutions for

tan (θ) = \frac{7}{5}

tan (x) = a \Rightarrow x = arctan (a) + πn

θ = arctan (\frac{7}{5}) + πn

θ = arctan (\frac{7}{5}) + πn

Show solutions in decimal form

θ = 0.95054 \dots + πn

cot^{2} (x) + 1 = sin^{2} (x)

(4 + tan (x)) (3 sin (x) - 2) = 0

sec (2 x) - 1 = 0

sin (2 x) + sin (x) + 2 cos (x) + 1 = 0

csc (x) = \frac{13}{5}

What is the general solution for 5tan(θ)-7=0 ?
The general solution for 5tan(θ)-7=0 is θ=0.95054…+pin