What is the general solution for sin(x)=-(sqrt(3))/2 ,0<= x<= 2pi ?

The general solution for sin(x)=-(sqrt(3))/2 ,0<= x<= 2pi is x=(4pi)/3 ,x=(5pi)/3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

sin(x)=-(sqrt(3))/2 ,0<= x<= 2pi

sin (x) = - \frac{3}{2}, 0 \leq x \leq 2 π

x = \frac{4 π}{3}, x = \frac{5 π}{3}

Solution steps

sin (x) = - \frac{3}{2}, 0 \leq x \leq 2 π

General solutions for

sin (x) = - \frac{3}{2}

x = \frac{4 π}{3} + 2 πn, x = \frac{5 π}{3} + 2 πn

Solutions for the range

0 \leq x \leq 2 π

x = \frac{4 π}{3}, x = \frac{5 π}{3}

sin^{2} (x) = 1 + cos^{2} (x)

cos^{2} (θ) = 0

cos (7 x) cos (2 x) + sin (7 x) sin (2 x) = \frac{1}{2}

sin (2 x) = \frac{1}{2}, 0 \leq x \leq 2 π

8 sin^{2} (θ) - 6 = 0

What is the general solution for sin(x)=-(sqrt(3))/2 ,0<= x<= 2pi ?
The general solution for sin(x)=-(sqrt(3))/2 ,0<= x<= 2pi is x=(4pi)/3 ,x=(5pi)/3