What is the general solution for 2cos(2θ)=1 ?

The general solution for 2cos(2θ)=1 is θ= pi/6+pin,θ=(5pi)/6+pin

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2cos(2θ)=1

2 cos (2 θ) = 1

θ = \frac{π}{6} + πn, θ = \frac{5 π}{6} + πn

Solution steps

2 cos (2 θ) = 1

Divide both sides by

2

cos (2 θ) = \frac{1}{2}

General solutions for

cos (2 θ) = \frac{1}{2}

2 θ = \frac{π}{3} + 2 πn, 2 θ = \frac{5 π}{3} + 2 πn

Solve

2 θ = \frac{π}{3} + 2 πn : θ = \frac{π}{6} + πn

Solve

2 θ = \frac{5 π}{3} + 2 πn : θ = \frac{5 π}{6} + πn

θ = \frac{π}{6} + πn, θ = \frac{5 π}{6} + πn

8 cos (θ) - 43 = 0

cos (x) = 1 + sin (x)

(tan (x) + 3) (cos (x) + 2) = 0

x, cos (y) + sin (x) = 1

cot (x) + 5 csc (x) = 6

What is the general solution for 2cos(2θ)=1 ?
The general solution for 2cos(2θ)=1 is θ= pi/6+pin,θ=(5pi)/6+pin