What is the general solution for cos(2θ)=sin(2θ) ?

The general solution for cos(2θ)=sin(2θ) is θ= pi/8+(pin)/2

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cos(2θ)=sin(2θ)

cos (2 θ) = sin (2 θ)

θ = \frac{π}{8} + \frac{πn}{2}

Solution steps

cos (2 θ) = sin (2 θ)

Rewrite using trig identities

tan (2 θ) = 1

General solutions for

tan (2 θ) = 1

2 θ = \frac{π}{4} + πn

Solve

2 θ = \frac{π}{4} + πn : θ = \frac{π}{8} + \frac{πn}{2}

θ = \frac{π}{8} + \frac{πn}{2}

2 cos (\frac{x}{2}) = 3

tan (x) (cot (x) - \frac{3}{3}) = 0

24 sin^{2} (x) = 24 - 12 cos (x)

3 tan (x) = 1

2 cos^{2} (t) + 3 cos (t) + 1 = 0

What is the general solution for cos(2θ)=sin(2θ) ?
The general solution for cos(2θ)=sin(2θ) is θ= pi/8+(pin)/2