What is the general solution for cos(2θ)=-(sqrt(2))/2 ?

The general solution for cos(2θ)=-(sqrt(2))/2 is θ=(3pi)/8+pin,θ=(5pi)/8+pin

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cos(2θ)=-(sqrt(2))/2

cos (2 θ) = - \frac{2}{2}

θ = \frac{3 π}{8} + πn, θ = \frac{5 π}{8} + πn

Solution steps

cos (2 θ) = - \frac{2}{2}

General solutions for

cos (2 θ) = - \frac{2}{2}

2 θ = \frac{3 π}{4} + 2 πn, 2 θ = \frac{5 π}{4} + 2 πn

Solve

2 θ = \frac{3 π}{4} + 2 πn : θ = \frac{3 π}{8} + πn

Solve

2 θ = \frac{5 π}{4} + 2 πn : θ = \frac{5 π}{8} + πn

θ = \frac{3 π}{8} + πn, θ = \frac{5 π}{8} + πn

tan (\frac{θ}{2} + \frac{π}{3}) = - 1

sin (2 x) = 3 cos (2 x)

sec (x) = - 2, 0 \leq x \leq 2 π

t, g = sin (2 π f t)

3 sin (x) - cos (x) = - 3

What is the general solution for cos(2θ)=-(sqrt(2))/2 ?
The general solution for cos(2θ)=-(sqrt(2))/2 is θ=(3pi)/8+pin,θ=(5pi)/8+pin