What is the general solution for cos(θ/2)=-(sqrt(3))/2 ?

The general solution for cos(θ/2)=-(sqrt(3))/2 is θ=(5pi)/3+4pin,θ=(7pi)/3+4pin

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cos(θ/2)=-(sqrt(3))/2

cos (\frac{θ}{2}) = - \frac{3}{2}

θ = \frac{5 π}{3} + 4 πn, θ = \frac{7 π}{3} + 4 πn

Solution steps

cos (\frac{θ}{2}) = - \frac{3}{2}

General solutions for

cos (\frac{θ}{2}) = - \frac{3}{2}

\frac{θ}{2} = \frac{5 π}{6} + 2 πn, \frac{θ}{2} = \frac{7 π}{6} + 2 πn

Solve

\frac{θ}{2} = \frac{5 π}{6} + 2 πn : θ = \frac{5 π}{3} + 4 πn

Solve

\frac{θ}{2} = \frac{7 π}{6} + 2 πn : θ = \frac{7 π}{3} + 4 πn

θ = \frac{5 π}{3} + 4 πn, θ = \frac{7 π}{3} + 4 πn

2 sin^{2} (x) = - sin (x)

3 sec (θ) = 2

cosh (x) = - 1

5 sin (2 θ) = 7 cos (2 θ)

cos (x) = \frac{- 1}{3}

What is the general solution for cos(θ/2)=-(sqrt(3))/2 ?
The general solution for cos(θ/2)=-(sqrt(3))/2 is θ=(5pi)/3+4pin,θ=(7pi)/3+4pin