What is the general solution for sin(x)=1,0<= x<= 2pi ?

The general solution for sin(x)=1,0<= x<= 2pi is x= pi/2

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sin(x)=1,0<= x<= 2pi

sin (x) = 1, 0 \leq x \leq 2 π

x = \frac{π}{2}

Solution steps

sin (x) = 1, 0 \leq x \leq 2 π

General solutions for

sin (x) = 1

x = \frac{π}{2} + 2 πn

Solutions for the range

0 \leq x \leq 2 π

x = \frac{π}{2}

6 csc (θ) - 6 = 0

9 sin (x) tan (x) + 4 tan (x) = 0

x, f [g] = cos (\frac{1}{x ^{2}})

2 cos (\frac{π}{5} θ) = 3

2 cos (x) - sin (2 x) = 0

What is the general solution for sin(x)=1,0<= x<= 2pi ?
The general solution for sin(x)=1,0<= x<= 2pi is x= pi/2