What is the general solution for sin^2(θ)-16=0 ?

The general solution for sin^2(θ)-16=0 is No Solution for θ\in\mathbb{R}

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sin^2(θ)-16=0

sin^{2} (θ) - 16 = 0

No Solution for θ \in R

Solution steps

sin^{2} (θ) - 16 = 0

Solve by substitution

sin (θ) = 4, sin (θ) = - 4

sin (θ) = 4 :

No Solution

sin (θ) = - 4 :

No Solution

Combine all the solutions

No Solution for θ \in R

sin (x) + tan (x) = 0

sin^{2} (x) cos^{2} (x) = 0

3 sin (x) cos (x) + 5 cos (x) = 0

5 sin (x) tan (x) = - 7 tan (x)

cos (x + \frac{π}{2}) - cos (x - \frac{π}{2}) = 2

What is the general solution for sin^2(θ)-16=0 ?
The general solution for sin^2(θ)-16=0 is No Solution for θ\in\mathbb{R}