What is the general solution for sin^2(θ)=2sin(θ)+3 ?

The general solution for sin^2(θ)=2sin(θ)+3 is θ=(3pi)/2+2pin

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sin^2(θ)=2sin(θ)+3

sin^{2} (θ) = 2 sin (θ) + 3

θ = \frac{3 π}{2} + 2 πn

Solution steps

sin^{2} (θ) = 2 sin (θ) + 3

Solve by substitution

sin (θ) = 3, sin (θ) = - 1

sin (θ) = 3 :

No Solution

sin (θ) = - 1 : θ = \frac{3 π}{2} + 2 πn

Combine all the solutions

θ = \frac{3 π}{2} + 2 πn

sin (3 x) + sin (5 x) = 0

sec (x) = 1 - tan (x)

- cos (x) = cos (x)

2 cos (θ) - 1 = 0

6 sin^{2} (x) - 7 sin (x) + 2 = 0

What is the general solution for sin^2(θ)=2sin(θ)+3 ?
The general solution for sin^2(θ)=2sin(θ)+3 is θ=(3pi)/2+2pin