What is the general solution for cos^2(x)-sin^2(x)=-1 ?

The general solution for cos^2(x)-sin^2(x)=-1 is x= pi/2+pin

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cos^2(x)-sin^2(x)=-1

cos^{2} (x) - sin^{2} (x) = - 1

x = \frac{π}{2} + πn

Solution steps

cos^{2} (x) - sin^{2} (x) = - 1

Rewrite using trig identities

cos (2 x) = - 1

General solutions for

cos (2 x) = - 1

2 x = π + 2 πn

Solve

2 x = π + 2 πn : x = \frac{π}{2} + πn

x = \frac{π}{2} + πn

2 cos (2 x) = 2

4 cos^{2} (x) + 4 cos (x) + 1 = 0

sec (x) = \frac{1}{sin ( x )}

sin (x) sec (x) = 2 sin (x)

sin (θ) tan (θ) = sin (θ)

What is the general solution for cos^2(x)-sin^2(x)=-1 ?
The general solution for cos^2(x)-sin^2(x)=-1 is x= pi/2+pin