What is the general solution for 2sin^2(x)=sqrt(2)sin(x) ?

The general solution for 2sin^2(x)=sqrt(2)sin(x) is x=2pin,x=pi+2pin,x= pi/4+2pin,x=(3pi)/4+2pin

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2sin^2(x)=sqrt(2)sin(x)

2 sin^{2} (x) = 2 sin (x)

x = 2 πn, x = π + 2 πn, x = \frac{π}{4} + 2 πn, x = \frac{3 π}{4} + 2 πn

Solution steps

2 sin^{2} (x) = 2 sin (x)

Solve by substitution

sin (x) = 0, sin (x) = \frac{2}{2}

sin (x) = 0 : x = 2 πn, x = π + 2 πn

sin (x) = \frac{2}{2} : x = \frac{π}{4} + 2 πn, x = \frac{3 π}{4} + 2 πn

Combine all the solutions

x = 2 πn, x = π + 2 πn, x = \frac{π}{4} + 2 πn, x = \frac{3 π}{4} + 2 πn

cos (2 x) + 3 sin (x) - 2 = 0

tan (a) = 3

tan (x) = \frac{6}{8}

sin (\frac{1}{2} x) + cos (x) = 1

cos (x) tan^{2} (x) = cos (x)

What is the general solution for 2sin^2(x)=sqrt(2)sin(x) ?
The general solution for 2sin^2(x)=sqrt(2)sin(x) is x=2pin,x=pi+2pin,x= pi/4+2pin,x=(3pi)/4+2pin