What is the general solution for 2+4sin(θ)=0 ?

The general solution for 2+4sin(θ)=0 is θ=(7pi)/6+2pin,θ=(11pi)/6+2pin

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2+4sin(θ)=0

2 + 4 sin (θ) = 0

θ = \frac{7 π}{6} + 2 πn, θ = \frac{11 π}{6} + 2 πn

Solution steps

2 + 4 sin (θ) = 0

Move

2

to the right side

4 sin (θ) = - 2

Divide both sides by

4

sin (θ) = - \frac{1}{2}

General solutions for

sin (θ) = - \frac{1}{2}

θ = \frac{7 π}{6} + 2 πn, θ = \frac{11 π}{6} + 2 πn

73 cot (θ) + 4 = 25

x, sin (2 x) = cos (x)

4 tan (x) sin (x) = 3 sin (x)

3 sin (θ) + cos (θ) = 3

25 cos^{2} (θ) - 9 = 0

What is the general solution for 2+4sin(θ)=0 ?
The general solution for 2+4sin(θ)=0 is θ=(7pi)/6+2pin,θ=(11pi)/6+2pin