What is the general solution for 10sin^2(x)+11sin(x)-8=0 ?

The general solution for 10sin^2(x)+11sin(x)-8=0 is x= pi/6+2pin,x=(5pi)/6+2pin

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

10sin^2(x)+11sin(x)-8=0

10 sin^{2} (x) + 11 sin (x) - 8 = 0

x = \frac{π}{6} + 2 πn, x = \frac{5 π}{6} + 2 πn

Solution steps

10 sin^{2} (x) + 11 sin (x) - 8 = 0

Solve by substitution

sin (x) = \frac{1}{2}, sin (x) = - \frac{8}{5}

sin (x) = \frac{1}{2} : x = \frac{π}{6} + 2 πn, x = \frac{5 π}{6} + 2 πn

sin (x) = - \frac{8}{5} :

No Solution

Combine all the solutions

x = \frac{π}{6} + 2 πn, x = \frac{5 π}{6} + 2 πn

2 cos^{2} (x) + 7 cos (x) - 4 = 0

cot (2 θ) = \frac{3}{3}

4 sin^{2} (\frac{θ}{2}) + 8 cos (\frac{θ}{2}) - 7 = 0, 0 \leq θ \leq 36 0^{\circ}

- cos (θ) + 1 = 2 cos (θ) + 3

cot^{2} (x) + cot (x) = 0

What is the general solution for 10sin^2(x)+11sin(x)-8=0 ?
The general solution for 10sin^2(x)+11sin(x)-8=0 is x= pi/6+2pin,x=(5pi)/6+2pin