What is the general solution for cos(2x)*2=0 ?

The general solution for cos(2x)*2=0 is x= pi/4+pin,x=(3pi)/4+pin

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cos(2x)*2=0

cos (2 x) \cdot 2 = 0

x = \frac{π}{4} + πn, x = \frac{3 π}{4} + πn

Solution steps

cos (2 x) \cdot 2 = 0

Divide both sides by

2

cos (2 x) = 0

General solutions for

cos (2 x) = 0

2 x = \frac{π}{2} + 2 πn, 2 x = \frac{3 π}{2} + 2 πn

Solve

2 x = \frac{π}{2} + 2 πn : x = \frac{π}{4} + πn

Solve

2 x = \frac{3 π}{2} + 2 πn : x = \frac{3 π}{4} + πn

x = \frac{π}{4} + πn, x = \frac{3 π}{4} + πn

csc^{3} (x) + csc^{2} (x) = 4 csc (x) + 4

2 sin^{2} (x) - 5 sin (x) - 3 = 0

6 + 6 sin (θ) = 4 cos^{2} (θ)

5 cos (x) + 5 sin (x) tan (x) = 10

sin (x) = 0.33

What is the general solution for cos(2x)*2=0 ?
The general solution for cos(2x)*2=0 is x= pi/4+pin,x=(3pi)/4+pin