What is the general solution for 2cos(2x)=-1 ?

The general solution for 2cos(2x)=-1 is x= pi/3+pin,x=(2pi)/3+pin

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2cos(2x)=-1

2 cos (2 x) = - 1

x = \frac{π}{3} + πn, x = \frac{2 π}{3} + πn

Solution steps

2 cos (2 x) = - 1

Divide both sides by

2

cos (2 x) = - \frac{1}{2}

General solutions for

cos (2 x) = - \frac{1}{2}

2 x = \frac{2 π}{3} + 2 πn, 2 x = \frac{4 π}{3} + 2 πn

Solve

2 x = \frac{2 π}{3} + 2 πn : x = \frac{π}{3} + πn

Solve

2 x = \frac{4 π}{3} + 2 πn : x = \frac{2 π}{3} + πn

x = \frac{π}{3} + πn, x = \frac{2 π}{3} + πn

3 sin (x) + cos^{2} (x) = 2

5 sin (2 θ) - 7 sin (θ) = 0

cos (θ) = \frac{3}{3}

arctan (x + 1) + arctan (x - 1) = arctan (2)

2 sin^{2} (x) - 2 sin (x) = 0

What is the general solution for 2cos(2x)=-1 ?
The general solution for 2cos(2x)=-1 is x= pi/3+pin,x=(2pi)/3+pin