What is the general solution for sin(x/3)= 1/2 ,0<= x<= 2pi ?

The general solution for sin(x/3)= 1/2 ,0<= x<= 2pi is x= pi/2

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sin(x/3)= 1/2 ,0<= x<= 2pi

sin (\frac{x}{3}) = \frac{1}{2}, 0 \leq x \leq 2 π

x = \frac{π}{2}

Solution steps

sin (\frac{x}{3}) = \frac{1}{2}, 0 \leq x \leq 2 π

General solutions for

sin (\frac{x}{3}) = \frac{1}{2}

\frac{x}{3} = \frac{π}{6} + 2 πn, \frac{x}{3} = \frac{5 π}{6} + 2 πn

Solve

\frac{x}{3} = \frac{π}{6} + 2 πn : x = \frac{π}{2} + 6 πn

Solve

\frac{x}{3} = \frac{5 π}{6} + 2 πn : x = \frac{5 π}{2} + 6 πn

x = \frac{π}{2} + 6 πn, x = \frac{5 π}{2} + 6 πn

Solutions for the range

0 \leq x \leq 2 π

x = \frac{π}{2}

sin (θ) = - \frac{8}{17}

sin (\frac{θ}{2}) - cos (θ) = 0

12 sec^{2} (x) - 16 = 0

cos (3 x - \frac{π}{8}) = \frac{2}{2}

5 (1 - cos (θ)) = sin^{2} (θ)

What is the general solution for sin(x/3)= 1/2 ,0<= x<= 2pi ?
The general solution for sin(x/3)= 1/2 ,0<= x<= 2pi is x= pi/2