What is the general solution for cos(x)=1,0<= x<= 2pi ?

The general solution for cos(x)=1,0<= x<= 2pi is x=0,x=2pi

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cos(x)=1,0<= x<= 2pi

cos (x) = 1, 0 \leq x \leq 2 π

x = 0, x = 2 π

Solution steps

cos (x) = 1, 0 \leq x \leq 2 π

General solutions for

cos (x) = 1

x = 0 + 2 πn

Solve

x = 0 + 2 πn : x = 2 πn

x = 2 πn

Solutions for the range

0 \leq x \leq 2 π

x = 0, x = 2 π

x, cot (- x) cos (- x) + sin (- x) = \frac{- 1}{f}

tan^{2} (x) sin (x) = 3 sin (x)

cos (θ) - sin (2 θ) = 0

sin (7 x) = 0

cos (2 x) - 3 cos (x) = - 1

What is the general solution for cos(x)=1,0<= x<= 2pi ?
The general solution for cos(x)=1,0<= x<= 2pi is x=0,x=2pi