What is the general solution for 2sin(x)cos(x)= 1/2 ?

The general solution for 2sin(x)cos(x)= 1/2 is x= pi/(12)+pin,x=(5pi)/(12)+pin

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2sin(x)cos(x)= 1/2

2 sin (x) cos (x) = \frac{1}{2}

x = \frac{π}{12} + πn, x = \frac{5 π}{12} + πn

Solution steps

2 sin (x) cos (x) = \frac{1}{2}

Rewrite using trig identities

sin (2 x) = \frac{1}{2}

General solutions for

sin (2 x) = \frac{1}{2}

2 x = \frac{π}{6} + 2 πn, 2 x = \frac{5 π}{6} + 2 πn

Solve

2 x = \frac{π}{6} + 2 πn : x = \frac{π}{12} + πn

Solve

2 x = \frac{5 π}{6} + 2 πn : x = \frac{5 π}{12} + πn

x = \frac{π}{12} + πn, x = \frac{5 π}{12} + πn

tan (θ) = 0.75

cos (6 x) = 1

csc^{2} (θ) - 2 csc (θ) = 0

cos (θ) = - \frac{7}{25}

3 cos (x) + 3 sin (x) tan (x) = 6

What is the general solution for 2sin(x)cos(x)= 1/2 ?
The general solution for 2sin(x)cos(x)= 1/2 is x= pi/(12)+pin,x=(5pi)/(12)+pin