What is the general solution for cos(5x)=(sqrt(3))/2 ?

The general solution for cos(5x)=(sqrt(3))/2 is x= pi/(30)+(2pin)/5 ,x=(11pi}{30}+\frac{2pin)/5

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cos(5x)=(sqrt(3))/2

Solution

cos (5 x) = \frac{3}{2}

Solution

x = \frac{π}{30} + \frac{2 πn}{5}, x = \frac{11 π}{30} + \frac{2 πn}{5}

Degrees

x = 6^{\circ} + 7 2^{\circ} n, x = 6 6^{\circ} + 7 2^{\circ} n

Solution steps

cos (5 x) = \frac{3}{2}

General solutions for

cos (5 x) = \frac{3}{2}

cos (x)

periodicity table with

2 πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} cos (x) 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} cos (x) - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2} 0 \frac{1}{2} \frac{2}{2} \frac{3}{2}

5 x = \frac{π}{6} + 2 πn, 5 x = \frac{11 π}{6} + 2 πn

5 x = \frac{π}{6} + 2 πn, 5 x = \frac{11 π}{6} + 2 πn

Solve

5 x = \frac{π}{6} + 2 πn : x = \frac{π}{30} + \frac{2 πn}{5}

5 x = \frac{π}{6} + 2 πn

Divide both sides by

5

5 x = \frac{π}{6} + 2 πn

Divide both sides by

5

\frac{5 x}{5} = \frac{\frac{π}{6}}{5} + \frac{2 πn}{5}

Simplify

\frac{5 x}{5} = \frac{\frac{π}{6}}{5} + \frac{2 πn}{5}

Simplify

\frac{5 x}{5} : x

\frac{5 x}{5}

Divide the numbers:

\frac{5}{5} = 1

= x

Simplify

\frac{\frac{π}{6}}{5} + \frac{2 πn}{5} : \frac{π}{30} + \frac{2 πn}{5}

\frac{\frac{π}{6}}{5} + \frac{2 πn}{5}

\frac{\frac{π}{6}}{5} = \frac{π}{30}

\frac{\frac{π}{6}}{5}

Apply the fraction rule:

\frac{\frac{b}{c}}{a} = \frac{b}{c \cdot a}

= \frac{π}{6 \cdot 5}

Multiply the numbers:

6 \cdot 5 = 30

= \frac{π}{30}

= \frac{π}{30} + \frac{2 πn}{5}

x = \frac{π}{30} + \frac{2 πn}{5}

x = \frac{π}{30} + \frac{2 πn}{5}

x = \frac{π}{30} + \frac{2 πn}{5}

Solve

5 x = \frac{11 π}{6} + 2 πn : x = \frac{11 π}{30} + \frac{2 πn}{5}

5 x = \frac{11 π}{6} + 2 πn

Divide both sides by

5

5 x = \frac{11 π}{6} + 2 πn

Divide both sides by

5

\frac{5 x}{5} = \frac{\frac{11 π}{6}}{5} + \frac{2 πn}{5}

Simplify

\frac{5 x}{5} = \frac{\frac{11 π}{6}}{5} + \frac{2 πn}{5}

Simplify

\frac{5 x}{5} : x

\frac{5 x}{5}

Divide the numbers:

\frac{5}{5} = 1

= x

Simplify

\frac{\frac{11 π}{6}}{5} + \frac{2 πn}{5} : \frac{11 π}{30} + \frac{2 πn}{5}

\frac{\frac{11 π}{6}}{5} + \frac{2 πn}{5}

\frac{\frac{11 π}{6}}{5} = \frac{11 π}{30}

\frac{\frac{11 π}{6}}{5}

Apply the fraction rule:

\frac{\frac{b}{c}}{a} = \frac{b}{c \cdot a}

= \frac{11 π}{6 \cdot 5}

Multiply the numbers:

6 \cdot 5 = 30

= \frac{11 π}{30}

= \frac{11 π}{30} + \frac{2 πn}{5}

x = \frac{11 π}{30} + \frac{2 πn}{5}

x = \frac{11 π}{30} + \frac{2 πn}{5}

x = \frac{11 π}{30} + \frac{2 πn}{5}

x = \frac{π}{30} + \frac{2 πn}{5}, x = \frac{11 π}{30} + \frac{2 πn}{5}

Popular Examples

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cos(2x)-sin(2x)=0

cos (2 x) - sin (2 x) = 0

cos(5θ)=0

cos (5 θ) = 0

sin(θ)=csc(θ)

sin (θ) = csc (θ)

-5sin(x)=0,0<= x<= 2pi

- 5 sin (x) = 0, 0 \leq x \leq 2 π

Frequently Asked Questions (FAQ)

What is the general solution for cos(5x)=(sqrt(3))/2 ?
The general solution for cos(5x)=(sqrt(3))/2 is x= pi/(30)+(2pin)/5 ,x=(11pi}{30}+\frac{2pin)/5