What is the general solution for 4sin(2x)=2 ?

The general solution for 4sin(2x)=2 is x= pi/(12)+pin,x=(5pi)/(12)+pin

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4sin(2x)=2

4 sin (2 x) = 2

x = \frac{π}{12} + πn, x = \frac{5 π}{12} + πn

Solution steps

4 sin (2 x) = 2

Divide both sides by

4

sin (2 x) = \frac{1}{2}

General solutions for

sin (2 x) = \frac{1}{2}

2 x = \frac{π}{6} + 2 πn, 2 x = \frac{5 π}{6} + 2 πn

Solve

2 x = \frac{π}{6} + 2 πn : x = \frac{π}{12} + πn

Solve

2 x = \frac{5 π}{6} + 2 πn : x = \frac{5 π}{12} + πn

x = \frac{π}{12} + πn, x = \frac{5 π}{12} + πn

3 sin^{2} (x) = - 7 sin (x) - 4, 0 \leq x \leq 2 π

sin (- θ) = sin (θ)

4 cos^{2} (x) + 4 cos (x) = 3

sec (2 x) csc (2 x) = 2 csc (2 x)

3 cos (x) tan (x) = - 10 tan (x)

What is the general solution for 4sin(2x)=2 ?
The general solution for 4sin(2x)=2 is x= pi/(12)+pin,x=(5pi)/(12)+pin