What is the general solution for sin(x)=-1,0<= x<= 2pi ?

The general solution for sin(x)=-1,0<= x<= 2pi is x=(3pi)/2

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sin(x)=-1,0<= x<= 2pi

sin (x) = - 1, 0 \leq x \leq 2 π

x = \frac{3 π}{2}

Solution steps

sin (x) = - 1, 0 \leq x \leq 2 π

General solutions for

sin (x) = - 1

x = \frac{3 π}{2} + 2 πn

Solutions for the range

0 \leq x \leq 2 π

x = \frac{3 π}{2}

- 3 sin (x) + cos (x) = 0

2 sin^{2} (x) + 5 cos (x) - 4 = 0

cos (2 x) = 3 sin (x) - 1

2 sin (2 x) = - 1

2 sec (x) tan (x) - sec^{2} (x) = 0

What is the general solution for sin(x)=-1,0<= x<= 2pi ?
The general solution for sin(x)=-1,0<= x<= 2pi is x=(3pi)/2