What is the general solution for sin(5t)-1=0 ?

The general solution for sin(5t)-1=0 is t= pi/(10)+(2pin)/5

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sin(5t)-1=0

sin (5 t) - 1 = 0

t = \frac{π}{10} + \frac{2 πn}{5}

Solution steps

sin (5 t) - 1 = 0

Move

1

to the right side

sin (5 t) = 1

General solutions for

sin (5 t) = 1

5 t = \frac{π}{2} + 2 πn

Solve

5 t = \frac{π}{2} + 2 πn : t = \frac{π}{10} + \frac{2 πn}{5}

t = \frac{π}{10} + \frac{2 πn}{5}

2 sin (θ) cos (θ) - sin (θ) = 0

9 sin (x) tan (x) - 2 tan (x) = 0

3 cot (3 x) + 1 = 0

tan (4 x) = 3

cos (x) + 2 = - cos (x)

What is the general solution for sin(5t)-1=0 ?
The general solution for sin(5t)-1=0 is t= pi/(10)+(2pin)/5