What is the general solution for 1+cos(x)=1-cos(x) ?

The general solution for 1+cos(x)=1-cos(x) is x= pi/2+2pin,x=(3pi)/2+2pin

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1+cos(x)=1-cos(x)

1 + cos (x) = 1 - cos (x)

x = \frac{π}{2} + 2 πn, x = \frac{3 π}{2} + 2 πn

Solution steps

1 + cos (x) = 1 - cos (x)

Solve by substitution

cos (x) = 0

cos (x) = 0 : x = \frac{π}{2} + 2 πn, x = \frac{3 π}{2} + 2 πn

Combine all the solutions

x = \frac{π}{2} + 2 πn, x = \frac{3 π}{2} + 2 πn

csc (x) = 1 - cot (x)

sin (x) = 0.7547

cos (2 x - \frac{π}{6}) = \frac{( 3 )}{2}, 0 < x < 2 π

- 1 = tan (x)

sin (2 x) = \frac{3}{2}, 0 \leq x \leq 2 π

What is the general solution for 1+cos(x)=1-cos(x) ?
The general solution for 1+cos(x)=1-cos(x) is x= pi/2+2pin,x=(3pi)/2+2pin