What is the general solution for -sin^2(x)=2cos(x)-2 ?

The general solution for -sin^2(x)=2cos(x)-2 is x=2pin

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

-sin^2(x)=2cos(x)-2

- sin^{2} (x) = 2 cos (x) - 2

x = 2 πn

Solution steps

- sin^{2} (x) = 2 cos (x) - 2

Subtract

2 cos (x) - 2

from both sides

- sin^{2} (x) - 2 cos (x) + 2 = 0

Rewrite using trig identities

1 + cos^{2} (x) - 2 cos (x) = 0

Solve by substitution

cos (x) = 1

cos (x) = 1 : x = 2 πn

Combine all the solutions

x = 2 πn

3 sin (2 θ) - 5 sin (θ) = 0

cos (2 x) = cos (x), 0 \leq x \leq 2 π

tan (x) = \frac{3}{2}

cos (x) = \frac{7}{13}

cos (\frac{π}{2} x) = 0

What is the general solution for -sin^2(x)=2cos(x)-2 ?
The general solution for -sin^2(x)=2cos(x)-2 is x=2pin